Base | Representation |
---|---|
bin | 1011011000011100010010… |
… | …1101100111010111110010 |
3 | 1122022101012210220122002122 |
4 | 2312013010231213113302 |
5 | 3120014234221302310 |
6 | 42341033400314242 |
7 | 2431100653036310 |
oct | 266070455472762 |
9 | 48271183818078 |
10 | 12514540025330 |
11 | 3a95428655562 |
12 | 14a149a172982 |
13 | 6ca167ca6835 |
14 | 3139c7ccd0b0 |
15 | 16a7ea2a9555 |
hex | b61c4b675f2 |
12514540025330 has 32 divisors (see below), whose sum is σ = 25744480746624. Its totient is φ = 4290652083456.
The previous prime is 12514540025311. The next prime is 12514540025359. The reversal of 12514540025330 is 3352004541521.
It is a super-2 number, since 2×125145400253302 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5725274 + ... + 7603146.
It is an arithmetic number, because the mean of its divisors is an integer number (804515023332).
Almost surely, 212514540025330 is an apocalyptic number.
12514540025330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12514540025330 is an abundant number, since it is smaller than the sum of its proper divisors (13229940721294).
12514540025330 is a wasteful number, since it uses less digits than its factorization.
12514540025330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1973090.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 12514540025330 its reverse (3352004541521), we get a palindrome (15866544566851).
The spelling of 12514540025330 in words is "twelve trillion, five hundred fourteen billion, five hundred forty million, twenty-five thousand, three hundred thirty".
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