1251530102531 has 2 divisors, whose sum is σ = 1251530102532. Its totient is φ = 1251530102530.

The previous prime is 1251530102479. The next prime is 1251530102533. The reversal of 1251530102531 is 1352010351521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1251530102531 - 2²⁶ = 1251462993667 is a prime.

It is a super-2 number, since 2×1251530102531² (a number of 25 digits) contains 22 as substring.

Together with 1251530102533, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1251530102494 and 1251530102503.

It is not a weakly prime, because it can be changed into another prime (1251530102533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625765051265 + 625765051266.

It is an arithmetic number, because the mean of its divisors is an integer number (625765051266).

Almost surely, 2^{1251530102531} is an apocalyptic number.

1251530102531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1251530102531 is an equidigital number, since it uses as much as digits as its factorization.

1251530102531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4500, while the sum is 29.

The spelling of 1251530102531 in words is "one trillion, two hundred fifty-one billion, five hundred thirty million, one hundred two thousand, five hundred thirty-one".