Base | Representation |
---|---|
bin | 11100011101001101110110… |
… | …100100111001011110101011 |
3 | 121102010111212122022221012202 |
4 | 130131031312210321132223 |
5 | 112401001412101003001 |
6 | 1122102302530130415 |
7 | 35235003015443663 |
oct | 3435156644713653 |
9 | 542114778287182 |
10 | 125153041422251 |
11 | 3697211a171427 |
12 | 120535b8420a0b |
13 | 54aab5bbc890b |
14 | 22c96220b31a3 |
15 | e707b797d96b |
hex | 71d3769397ab |
125153041422251 has 2 divisors, whose sum is σ = 125153041422252. Its totient is φ = 125153041422250.
The previous prime is 125153041422191. The next prime is 125153041422341. The reversal of 125153041422251 is 152224140351521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 125153041422251 - 210 = 125153041421227 is a prime.
It is not a weakly prime, because it can be changed into another prime (125153041452251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62576520711125 + 62576520711126.
It is an arithmetic number, because the mean of its divisors is an integer number (62576520711126).
Almost surely, 2125153041422251 is an apocalyptic number.
125153041422251 is a deficient number, since it is larger than the sum of its proper divisors (1).
125153041422251 is an equidigital number, since it uses as much as digits as its factorization.
125153041422251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96000, while the sum is 38.
Adding to 125153041422251 its reverse (152224140351521), we get a palindrome (277377181773772).
The spelling of 125153041422251 in words is "one hundred twenty-five trillion, one hundred fifty-three billion, forty-one million, four hundred twenty-two thousand, two hundred fifty-one".
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