125170127 has 2 divisors, whose sum is σ = 125170128. Its totient is φ = 125170126.

The previous prime is 125170079. The next prime is 125170141. The reversal of 125170127 is 721071521.

It is a strong prime.

It is an emirp because it is prime and its reverse (721071521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125170127 - 2⁶ = 125170063 is a prime.

It is a super-3 number, since 3×125170127³ (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 125170096 and 125170105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125170147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62585063 + 62585064.

It is an arithmetic number, because the mean of its divisors is an integer number (62585064).

Almost surely, 2^125170127 is an apocalyptic number.

125170127 is a deficient number, since it is larger than the sum of its proper divisors (1).

125170127 is an equidigital number, since it uses as much as digits as its factorization.

125170127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 980, while the sum is 26.

The square root of 125170127 is about 11187.9456112371. The cubic root of 125170127 is about 500.2267331686.

The spelling of 125170127 in words is "one hundred twenty-five million, one hundred seventy thousand, one hundred twenty-seven".