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12517230853 is a prime number
BaseRepresentation
bin10111010100001010…
…11100100100000101
31012022100101012200201
423222011130210011
5201113402341403
65430023410501
7622121464261
oct135205344405
935270335621
1012517230853
115343717896
122513bb3a31
13124637079a
1486a5bb0a1
154d3d8e21d
hex2ea15c905

12517230853 has 2 divisors, whose sum is σ = 12517230854. Its totient is φ = 12517230852.

The previous prime is 12517230841. The next prime is 12517230863. The reversal of 12517230853 is 35803271521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9393874084 + 3123356769 = 96922^2 + 55887^2 .

It is an emirp because it is prime and its reverse (35803271521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12517230853 - 225 = 12483676421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12517230863) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6258615426 + 6258615427.

It is an arithmetic number, because the mean of its divisors is an integer number (6258615427).

Almost surely, 212517230853 is an apocalyptic number.

It is an amenable number.

12517230853 is a deficient number, since it is larger than the sum of its proper divisors (1).

12517230853 is an equidigital number, since it uses as much as digits as its factorization.

12517230853 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 37.

It can be divided in two parts, 125172 and 30853, that added together give a square (156025 = 3952).

The spelling of 12517230853 in words is "twelve billion, five hundred seventeen million, two hundred thirty thousand, eight hundred fifty-three".