Base | Representation |
---|---|
bin | 1011011000101111010111… |
… | …1001010010111101100111 |
3 | 1122022212102122022022201221 |
4 | 2312023311321102331213 |
5 | 3120110230443411333 |
6 | 42343241422201211 |
7 | 2431341564215431 |
oct | 266136571227547 |
9 | 48285378268657 |
10 | 12519660138343 |
11 | 3a97615841216 |
12 | 14a2488a23207 |
13 | 6ca7a299b8c7 |
14 | 313d51cd9651 |
15 | 16a9e9a39d2d |
hex | b62f5e52f67 |
12519660138343 has 2 divisors, whose sum is σ = 12519660138344. Its totient is φ = 12519660138342.
The previous prime is 12519660138313. The next prime is 12519660138371. The reversal of 12519660138343 is 34383106691521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12519660138343 - 237 = 12382221184871 is a prime.
It is a super-2 number, since 2×125196601383432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12519660138313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6259830069171 + 6259830069172.
It is an arithmetic number, because the mean of its divisors is an integer number (6259830069172).
Almost surely, 212519660138343 is an apocalyptic number.
12519660138343 is a deficient number, since it is larger than the sum of its proper divisors (1).
12519660138343 is an equidigital number, since it uses as much as digits as its factorization.
12519660138343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2799360, while the sum is 52.
The spelling of 12519660138343 in words is "twelve trillion, five hundred nineteen billion, six hundred sixty million, one hundred thirty-eight thousand, three hundred forty-three".
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