12520200340237 has 2 divisors, whose sum is σ = 12520200340238. Its totient is φ = 12520200340236.

The previous prime is 12520200340183. The next prime is 12520200340243. The reversal of 12520200340237 is 73204300202521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11160537066121 + 1359663274116 = 3340739^2 + 1166046^2 .

It is a cyclic number.

It is not a de Polignac number, because 12520200340237 - 2³⁵ = 12485840601869 is a prime.

It is a super-2 number, since 2×12520200340237² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12520200340199 and 12520200340208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12520200310237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6260100170118 + 6260100170119.

It is an arithmetic number, because the mean of its divisors is an integer number (6260100170119).

Almost surely, 2^{12520200340237} is an apocalyptic number.

It is an amenable number.

12520200340237 is a deficient number, since it is larger than the sum of its proper divisors (1).

12520200340237 is an equidigital number, since it uses as much as digits as its factorization.

12520200340237 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 31.

Adding to 12520200340237 its reverse (73204300202521), we get a palindrome (85724500542758).

The spelling of 12520200340237 in words is "twelve trillion, five hundred twenty billion, two hundred million, three hundred forty thousand, two hundred thirty-seven".