Base | Representation |
---|---|
bin | 10010001110011001101… |
… | …001010111100010111011 |
3 | 11102201200211110122122021 |
4 | 102032121221113202323 |
5 | 131004420242212111 |
6 | 2355203430135311 |
7 | 156324652622254 |
oct | 22163151274273 |
9 | 4381624418567 |
10 | 1252413241531 |
11 | 443166696231 |
12 | 1828867b1537 |
13 | 911432cb4aa |
14 | 4488d563b2b |
15 | 228a136ed71 |
hex | 12399a578bb |
1252413241531 has 2 divisors, whose sum is σ = 1252413241532. Its totient is φ = 1252413241530.
The previous prime is 1252413241517. The next prime is 1252413241633. The reversal of 1252413241531 is 1351423142521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1252413241531 - 29 = 1252413241019 is a prime.
It is a super-2 number, since 2×12524132415312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1252413241831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626206620765 + 626206620766.
It is an arithmetic number, because the mean of its divisors is an integer number (626206620766).
Almost surely, 21252413241531 is an apocalyptic number.
1252413241531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1252413241531 is an equidigital number, since it uses as much as digits as its factorization.
1252413241531 is an evil number, because the sum of its binary digits is even.
The product of its digits is 28800, while the sum is 34.
The spelling of 1252413241531 in words is "one trillion, two hundred fifty-two billion, four hundred thirteen million, two hundred forty-one thousand, five hundred thirty-one".
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