Base | Representation |
---|---|
bin | 10010001110011111100… |
… | …111011010110111011001 |
3 | 11102201221210220221012001 |
4 | 102032133213122313121 |
5 | 131010121412103022 |
6 | 2355221404521001 |
7 | 156330310121335 |
oct | 22163747326731 |
9 | 4381853827161 |
10 | 1252513394137 |
11 | 443208181385 |
12 | 1828b4250161 |
13 | 9115ac965a5 |
14 | 4489c9947c5 |
15 | 228aa054b27 |
hex | 1239f9dadd9 |
1252513394137 has 2 divisors, whose sum is σ = 1252513394138. Its totient is φ = 1252513394136.
The previous prime is 1252513394129. The next prime is 1252513394141. The reversal of 1252513394137 is 7314933152521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 937364766976 + 315148627161 = 968176^2 + 561381^2 .
It is an emirp because it is prime and its reverse (7314933152521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1252513394137 - 23 = 1252513394129 is a prime.
It is not a weakly prime, because it can be changed into another prime (1252513395137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626256697068 + 626256697069.
It is an arithmetic number, because the mean of its divisors is an integer number (626256697069).
Almost surely, 21252513394137 is an apocalyptic number.
It is an amenable number.
1252513394137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1252513394137 is an equidigital number, since it uses as much as digits as its factorization.
1252513394137 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 680400, while the sum is 46.
The spelling of 1252513394137 in words is "one trillion, two hundred fifty-two billion, five hundred thirteen million, three hundred ninety-four thousand, one hundred thirty-seven".
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