1252515250139 has 2 divisors, whose sum is σ = 1252515250140. Its totient is φ = 1252515250138.

The previous prime is 1252515250099. The next prime is 1252515250141. The reversal of 1252515250139 is 9310525152521.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1252515250139 is a prime.

Together with 1252515250141, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1252515250096 and 1252515250105.

It is not a weakly prime, because it can be changed into another prime (1252515250739) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626257625069 + 626257625070.

It is an arithmetic number, because the mean of its divisors is an integer number (626257625070).

Almost surely, 2^{1252515250139} is an apocalyptic number.

1252515250139 is a deficient number, since it is larger than the sum of its proper divisors (1).

1252515250139 is an equidigital number, since it uses as much as digits as its factorization.

1252515250139 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135000, while the sum is 41.

The spelling of 1252515250139 in words is "one trillion, two hundred fifty-two billion, five hundred fifteen million, two hundred fifty thousand, one hundred thirty-nine".