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12525450666319 is a prime number
BaseRepresentation
bin1011011001000100111100…
…0010011010000101001111
31122100102101012012121211001
42312101033002122011033
53120204110332310234
642350040153241131
72431635225666253
oct266211702320517
948312335177731
1012525450666319
113a9a0173aa628
1214a36241031a7
136cb1b6544c16
14314340d7c263
1516ac38096d14
hexb644f09a14f

12525450666319 has 2 divisors, whose sum is σ = 12525450666320. Its totient is φ = 12525450666318.

The previous prime is 12525450666277. The next prime is 12525450666349. The reversal of 12525450666319 is 91366605452521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12525450666319 - 235 = 12491090927951 is a prime.

It is a super-2 number, since 2×125254506663192 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12525450666319.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12525450666349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6262725333159 + 6262725333160.

It is an arithmetic number, because the mean of its divisors is an integer number (6262725333160).

Almost surely, 212525450666319 is an apocalyptic number.

12525450666319 is a deficient number, since it is larger than the sum of its proper divisors (1).

12525450666319 is an equidigital number, since it uses as much as digits as its factorization.

12525450666319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664000, while the sum is 55.

The spelling of 12525450666319 in words is "twelve trillion, five hundred twenty-five billion, four hundred fifty million, six hundred sixty-six thousand, three hundred nineteen".