Base | Representation |
---|---|
bin | 10010001110100001110… |
… | …100110000000111000001 |
3 | 11102202001101122020022002 |
4 | 102032201310300013001 |
5 | 131010210403142312 |
6 | 2355225210553345 |
7 | 156331240050005 |
oct | 22164164600701 |
9 | 4382041566262 |
10 | 1252550443457 |
11 | 443227087055 |
12 | 182904738855 |
13 | 91165869071 |
14 | 448a387a705 |
15 | 228ad4224c2 |
hex | 123a1d301c1 |
1252550443457 has 2 divisors, whose sum is σ = 1252550443458. Its totient is φ = 1252550443456.
The previous prime is 1252550443453. The next prime is 1252550443471. The reversal of 1252550443457 is 7543440552521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1251364398736 + 1186044721 = 1118644^2 + 34439^2 .
It is a cyclic number.
It is not a de Polignac number, because 1252550443457 - 22 = 1252550443453 is a prime.
It is a super-2 number, since 2×12525504434572 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1252550443453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626275221728 + 626275221729.
It is an arithmetic number, because the mean of its divisors is an integer number (626275221729).
Almost surely, 21252550443457 is an apocalyptic number.
It is an amenable number.
1252550443457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1252550443457 is an equidigital number, since it uses as much as digits as its factorization.
1252550443457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3360000, while the sum is 47.
Adding to 1252550443457 its reverse (7543440552521), we get a palindrome (8795990995978).
The spelling of 1252550443457 in words is "one trillion, two hundred fifty-two billion, five hundred fifty million, four hundred forty-three thousand, four hundred fifty-seven".
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