Base | Representation |
---|---|
bin | 100101010101001… |
… | …0100100000101111 |
3 | 10020022000002012122 |
4 | 1022222110200233 |
5 | 10031131424142 |
6 | 324143423155 |
7 | 43016664335 |
oct | 11252244057 |
9 | 3208002178 |
10 | 1252608047 |
11 | 593078a69 |
12 | 2ab5b4abb |
13 | 16c6839c2 |
14 | bc505b55 |
15 | 74e7d1d2 |
hex | 4aa9482f |
1252608047 has 2 divisors, whose sum is σ = 1252608048. Its totient is φ = 1252608046.
The previous prime is 1252608043. The next prime is 1252608061. The reversal of 1252608047 is 7408062521.
It is a weak prime.
It is an emirp because it is prime and its reverse (7408062521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1252608047 - 22 = 1252608043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1252607998 and 1252608016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1252608043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626304023 + 626304024.
It is an arithmetic number, because the mean of its divisors is an integer number (626304024).
Almost surely, 21252608047 is an apocalyptic number.
1252608047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1252608047 is an equidigital number, since it uses as much as digits as its factorization.
1252608047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 35.
The square root of 1252608047 is about 35392.2031950541. The cubic root of 1252608047 is about 1077.9660068357.
The spelling of 1252608047 in words is "one billion, two hundred fifty-two million, six hundred eight thousand, forty-seven".
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