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12526663454341 is a prime number
BaseRepresentation
bin1011011001001001011101…
…0100110100111010000101
31122100112111201021122012221
42312102113110310322011
53120214101321014331
642350400355412341
72432010253345351
oct266222724647205
948315451248187
1012526663454341
113a9a589a50183
1214a39022b40b1
136cb34a895c7a
1431441807a461
1516aca97ab711
hexb6497534e85

12526663454341 has 2 divisors, whose sum is σ = 12526663454342. Its totient is φ = 12526663454340.

The previous prime is 12526663454321. The next prime is 12526663454359. The reversal of 12526663454341 is 14345436662521.

12526663454341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11768638997025 + 758024457316 = 3430545^2 + 870646^2 .

It is a cyclic number.

It is not a de Polignac number, because 12526663454341 - 217 = 12526663323269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12526663454321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6263331727170 + 6263331727171.

It is an arithmetic number, because the mean of its divisors is an integer number (6263331727171).

Almost surely, 212526663454341 is an apocalyptic number.

It is an amenable number.

12526663454341 is a deficient number, since it is larger than the sum of its proper divisors (1).

12526663454341 is an equidigital number, since it uses as much as digits as its factorization.

12526663454341 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12441600, while the sum is 52.

The spelling of 12526663454341 in words is "twelve trillion, five hundred twenty-six billion, six hundred sixty-three million, four hundred fifty-four thousand, three hundred forty-one".