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125291415127 is a prime number
BaseRepresentation
bin111010010101111110…
…0110100011001010111
3102222101202220100110111
41310223330310121113
54023044100241002
6133320313503451
712023560312444
oct1645374643127
9388352810414
10125291415127
114915481267a
1220347a11b87
13ba79529338
1460c7dc49cb
1533d47c23d7
hex1d2bf34657

125291415127 has 2 divisors, whose sum is σ = 125291415128. Its totient is φ = 125291415126.

The previous prime is 125291415091. The next prime is 125291415157. The reversal of 125291415127 is 721514192521.

It is a strong prime.

It is an emirp because it is prime and its reverse (721514192521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125291415127 - 27 = 125291414999 is a prime.

It is a super-2 number, since 2×1252914151272 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 125291415127.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125291415157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62645707563 + 62645707564.

It is an arithmetic number, because the mean of its divisors is an integer number (62645707564).

Almost surely, 2125291415127 is an apocalyptic number.

125291415127 is a deficient number, since it is larger than the sum of its proper divisors (1).

125291415127 is an equidigital number, since it uses as much as digits as its factorization.

125291415127 is an evil number, because the sum of its binary digits is even.

The product of its digits is 50400, while the sum is 40.

The spelling of 125291415127 in words is "one hundred twenty-five billion, two hundred ninety-one million, four hundred fifteen thousand, one hundred twenty-seven".