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125293942098671 is a prime number
BaseRepresentation
bin11100011111010001000100…
…111010010100101011101111
3121102121222120020210220201212
4130133101010322110223233
5112410303443134124141
61122251124204425035
735251121454440033
oct3437210472245357
9542558506726655
10125293942098671
1136a169539aa045
121207697b84817b
1354bb225260128
1422d238b1961c3
15e742b27b22eb
hex71f444e94aef

125293942098671 has 2 divisors, whose sum is σ = 125293942098672. Its totient is φ = 125293942098670.

The previous prime is 125293942098641. The next prime is 125293942098697. The reversal of 125293942098671 is 176890249392521.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125293942098671 is a prime.

It is a super-2 number, since 2×1252939420986712 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125293942098641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62646971049335 + 62646971049336.

It is an arithmetic number, because the mean of its divisors is an integer number (62646971049336).

It is a 1-persistent number, because it is pandigital, but 2⋅125293942098671 = 250587884197342 is not.

Almost surely, 2125293942098671 is an apocalyptic number.

125293942098671 is a deficient number, since it is larger than the sum of its proper divisors (1).

125293942098671 is an equidigital number, since it uses as much as digits as its factorization.

125293942098671 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 117573120, while the sum is 68.

The spelling of 125293942098671 in words is "one hundred twenty-five trillion, two hundred ninety-three billion, nine hundred forty-two million, ninety-eight thousand, six hundred seventy-one".