Base | Representation |
---|---|
bin | 11100011111010001000100… |
… | …111010010100101011101111 |
3 | 121102121222120020210220201212 |
4 | 130133101010322110223233 |
5 | 112410303443134124141 |
6 | 1122251124204425035 |
7 | 35251121454440033 |
oct | 3437210472245357 |
9 | 542558506726655 |
10 | 125293942098671 |
11 | 36a169539aa045 |
12 | 1207697b84817b |
13 | 54bb225260128 |
14 | 22d238b1961c3 |
15 | e742b27b22eb |
hex | 71f444e94aef |
125293942098671 has 2 divisors, whose sum is σ = 125293942098672. Its totient is φ = 125293942098670.
The previous prime is 125293942098641. The next prime is 125293942098697. The reversal of 125293942098671 is 176890249392521.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-125293942098671 is a prime.
It is a super-2 number, since 2×1252939420986712 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125293942098641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62646971049335 + 62646971049336.
It is an arithmetic number, because the mean of its divisors is an integer number (62646971049336).
It is a 1-persistent number, because it is pandigital, but 2⋅125293942098671 = 250587884197342 is not.
Almost surely, 2125293942098671 is an apocalyptic number.
125293942098671 is a deficient number, since it is larger than the sum of its proper divisors (1).
125293942098671 is an equidigital number, since it uses as much as digits as its factorization.
125293942098671 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 117573120, while the sum is 68.
The spelling of 125293942098671 in words is "one hundred twenty-five trillion, two hundred ninety-three billion, nine hundred forty-two million, ninety-eight thousand, six hundred seventy-one".
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