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12529804811 is a prime number
BaseRepresentation
bin10111010101101010…
…11010011000001011
31012100020001000220212
423222311122120023
5201130112223221
65431153111335
7622333404116
oct135265323013
935306030825
1012529804811
11534a825897
12251825854b
131248b53ab4
1486c13157d
154d5024b5b
hex2ead5a60b

12529804811 has 2 divisors, whose sum is σ = 12529804812. Its totient is φ = 12529804810.

The previous prime is 12529804697. The next prime is 12529804813. The reversal of 12529804811 is 11840892521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12529804811 - 218 = 12529542667 is a prime.

Together with 12529804813, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12529804813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6264902405 + 6264902406.

It is an arithmetic number, because the mean of its divisors is an integer number (6264902406).

Almost surely, 212529804811 is an apocalyptic number.

12529804811 is a deficient number, since it is larger than the sum of its proper divisors (1).

12529804811 is an equidigital number, since it uses as much as digits as its factorization.

12529804811 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46080, while the sum is 41.

The spelling of 12529804811 in words is "twelve billion, five hundred twenty-nine million, eight hundred four thousand, eight hundred eleven".