Base | Representation |
---|---|
bin | 1011011001011010110111… |
… | …0011010101111101101011 |
3 | 1122100222120022121011120202 |
4 | 2312112231303111331223 |
5 | 3120303133343120412 |
6 | 42352452134142415 |
7 | 2432234114300345 |
oct | 266265563257553 |
9 | 48328508534522 |
10 | 12531335520107 |
11 | 3aa1567234358 |
12 | 14a47a6ab1a0b |
13 | 6cb9137c6121 |
14 | 31473c776295 |
15 | 16ae7ea373c2 |
hex | b65adcd5f6b |
12531335520107 has 2 divisors, whose sum is σ = 12531335520108. Its totient is φ = 12531335520106.
The previous prime is 12531335519981. The next prime is 12531335520133. The reversal of 12531335520107 is 70102553313521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12531335520107 - 214 = 12531335503723 is a prime.
It is not a weakly prime, because it can be changed into another prime (12531385520107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6265667760053 + 6265667760054.
It is an arithmetic number, because the mean of its divisors is an integer number (6265667760054).
Almost surely, 212531335520107 is an apocalyptic number.
12531335520107 is a deficient number, since it is larger than the sum of its proper divisors (1).
12531335520107 is an equidigital number, since it uses as much as digits as its factorization.
12531335520107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 94500, while the sum is 38.
Adding to 12531335520107 its reverse (70102553313521), we get a palindrome (82633888833628).
The spelling of 12531335520107 in words is "twelve trillion, five hundred thirty-one billion, three hundred thirty-five million, five hundred twenty thousand, one hundred seven".
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