125314323550331 has 2 divisors, whose sum is σ = 125314323550332. Its totient is φ = 125314323550330.

The previous prime is 125314323550291. The next prime is 125314323550333. The reversal of 125314323550331 is 133055323413521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 125314323550331 - 2¹⁰ = 125314323549307 is a prime.

It is a super-2 number, since 2×125314323550331² (a number of 29 digits) contains 22 as substring.

Together with 125314323550333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (125314323550333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62657161775165 + 62657161775166.

It is an arithmetic number, because the mean of its divisors is an integer number (62657161775166).

Almost surely, 2^{125314323550331} is an apocalyptic number.

125314323550331 is a deficient number, since it is larger than the sum of its proper divisors (1).

125314323550331 is an equidigital number, since it uses as much as digits as its factorization.

125314323550331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486000, while the sum is 41.

Adding to 125314323550331 its reverse (133055323413521), we get a palindrome (258369646963852).

The spelling of 125314323550331 in words is "one hundred twenty-five trillion, three hundred fourteen billion, three hundred twenty-three million, five hundred fifty thousand, three hundred thirty-one".