Base | Representation |
---|---|
bin | 10010001111010000100… |
… | …001111100010110011110 |
3 | 11102211002000010011102212 |
4 | 102033100201330112132 |
5 | 131013312003321024 |
6 | 2355435042120422 |
7 | 156356533402625 |
oct | 22172041742636 |
9 | 4384060104385 |
10 | 1253334042014 |
11 | 44359943526a |
12 | 182aa3050112 |
13 | 9125bcc8752 |
14 | 449399766bc |
15 | 22907109a0e |
hex | 123d087c59e |
1253334042014 has 4 divisors (see below), whose sum is σ = 1880001063024. Its totient is φ = 626667021006.
The previous prime is 1253334042007. The next prime is 1253334042017. The reversal of 1253334042014 is 4102404333521.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×12533340420142 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1253334042017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 313333510502 + ... + 313333510505.
It is an arithmetic number, because the mean of its divisors is an integer number (470000265756).
Almost surely, 21253334042014 is an apocalyptic number.
1253334042014 is a deficient number, since it is larger than the sum of its proper divisors (626667021010).
1253334042014 is an equidigital number, since it uses as much as digits as its factorization.
1253334042014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 626667021009.
The product of its (nonzero) digits is 34560, while the sum is 32.
Adding to 1253334042014 its reverse (4102404333521), we get a palindrome (5355738375535).
The spelling of 1253334042014 in words is "one trillion, two hundred fifty-three billion, three hundred thirty-four million, forty-two thousand, fourteen".
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