Base | Representation |
---|---|
bin | 10010001111010001001… |
… | …001000101111111110110 |
3 | 11102211002201102120210201 |
4 | 102033101021011333312 |
5 | 131013322120231032 |
6 | 2355440050111114 |
7 | 156360016546366 |
oct | 22172111057766 |
9 | 4384081376721 |
10 | 1253344305142 |
11 | 4435a4205096 |
12 | 182aa657b49a |
13 | 9126117ccc7 |
14 | 4493b0889a6 |
15 | 22907e858e7 |
hex | 123d1245ff6 |
1253344305142 has 4 divisors (see below), whose sum is σ = 1880016457716. Its totient is φ = 626672152570.
The previous prime is 1253344305131. The next prime is 1253344305181. The reversal of 1253344305142 is 2415034433521.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 313336076284 + ... + 313336076287.
It is an arithmetic number, because the mean of its divisors is an integer number (470004114429).
Almost surely, 21253344305142 is an apocalyptic number.
1253344305142 is a deficient number, since it is larger than the sum of its proper divisors (626672152574).
1253344305142 is an equidigital number, since it uses as much as digits as its factorization.
1253344305142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 626672152573.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 1253344305142 its reverse (2415034433521), we get a palindrome (3668378738663).
The spelling of 1253344305142 in words is "one trillion, two hundred fifty-three billion, three hundred forty-four million, three hundred five thousand, one hundred forty-two".
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