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1253344305643 is a prime number
BaseRepresentation
bin10010001111010001001…
…001000110000111101011
311102211002201102121111021
4102033101021012013223
5131013322120240033
62355440050113311
7156360016551013
oct22172111060753
94384081377437
101253344305643
114435a4205501
12182aa657b837
13912611802c1
144493b088c43
1522907e85b2d
hex123d12461eb

1253344305643 has 2 divisors, whose sum is σ = 1253344305644. Its totient is φ = 1253344305642.

The previous prime is 1253344305641. The next prime is 1253344305667. The reversal of 1253344305643 is 3465034433521.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1253344305643 - 21 = 1253344305641 is a prime.

Together with 1253344305641, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1253344305643.

It is not a weakly prime, because it can be changed into another prime (1253344305641) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626672152821 + 626672152822.

It is an arithmetic number, because the mean of its divisors is an integer number (626672152822).

Almost surely, 21253344305643 is an apocalyptic number.

1253344305643 is a deficient number, since it is larger than the sum of its proper divisors (1).

1253344305643 is an equidigital number, since it uses as much as digits as its factorization.

1253344305643 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1555200, while the sum is 43.

The spelling of 1253344305643 in words is "one trillion, two hundred fifty-three billion, three hundred forty-four million, three hundred five thousand, six hundred forty-three".