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125352012041 is a prime number
BaseRepresentation
bin111010010111110001…
…1111110100100001001
3102222112222220222210122
41310233203332210021
54023210103341131
6133330320353025
712025224344024
oct1645743764411
9388488828718
10125352012041
1149185a40a73
1220364175775
13ba88c54bb9
1460d207a1bb
1533d9c91d7b
hex1d2f8fe909

125352012041 has 2 divisors, whose sum is σ = 125352012042. Its totient is φ = 125352012040.

The previous prime is 125352012013. The next prime is 125352012043. The reversal of 125352012041 is 140210253521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85150158025 + 40201854016 = 291805^2 + 200504^2 .

It is a cyclic number.

It is not a de Polignac number, because 125352012041 - 230 = 124278270217 is a prime.

Together with 125352012043, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 125352012041.

It is not a weakly prime, because it can be changed into another prime (125352012043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62676006020 + 62676006021.

It is an arithmetic number, because the mean of its divisors is an integer number (62676006021).

Almost surely, 2125352012041 is an apocalyptic number.

It is an amenable number.

125352012041 is a deficient number, since it is larger than the sum of its proper divisors (1).

125352012041 is an equidigital number, since it uses as much as digits as its factorization.

125352012041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 125352012041 its reverse (140210253521), we get a palindrome (265562265562).

The spelling of 125352012041 in words is "one hundred twenty-five billion, three hundred fifty-two million, twelve thousand, forty-one".