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125352311153 is a prime number
BaseRepresentation
bin111010010111110010…
…1000111100101110001
3102222120000111012002212
41310233211013211301
54023210142424103
6133330331021505
712025230031046
oct1645745074561
9388500435085
10125352311153
1149186125773
122036429a895
13ba8902b0a4
1460d21171cd
1533d9d007d8
hex1d2f947971

125352311153 has 2 divisors, whose sum is σ = 125352311154. Its totient is φ = 125352311152.

The previous prime is 125352311141. The next prime is 125352311237. The reversal of 125352311153 is 351113253521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110022899809 + 15329411344 = 331697^2 + 123812^2 .

It is an emirp because it is prime and its reverse (351113253521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125352311153 - 216 = 125352245617 is a prime.

It is a super-2 number, since 2×1253523111532 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (125352311053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62676155576 + 62676155577.

It is an arithmetic number, because the mean of its divisors is an integer number (62676155577).

Almost surely, 2125352311153 is an apocalyptic number.

It is an amenable number.

125352311153 is a deficient number, since it is larger than the sum of its proper divisors (1).

125352311153 is an equidigital number, since it uses as much as digits as its factorization.

125352311153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13500, while the sum is 32.

Adding to 125352311153 its reverse (351113253521), we get a palindrome (476465564674).

The spelling of 125352311153 in words is "one hundred twenty-five billion, three hundred fifty-two million, three hundred eleven thousand, one hundred fifty-three".