Base | Representation |
---|---|
bin | 10111010110111001… |
… | …10101110001101011 |
3 | 1012100221111011000202 |
4 | 23223130311301223 |
5 | 201140234000101 |
6 | 5432202422415 |
7 | 622520302553 |
oct | 135334656153 |
9 | 35327434022 |
10 | 12540140651 |
11 | 5355645305 |
12 | 251b801a0b |
13 | 124b03248c |
14 | 86d662163 |
15 | 4d5db736b |
hex | 2eb735c6b |
12540140651 has 2 divisors, whose sum is σ = 12540140652. Its totient is φ = 12540140650.
The previous prime is 12540140623. The next prime is 12540140653. The reversal of 12540140651 is 15604104521.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12540140651 is a prime.
Together with 12540140653, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12540140653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6270070325 + 6270070326.
It is an arithmetic number, because the mean of its divisors is an integer number (6270070326).
Almost surely, 212540140651 is an apocalyptic number.
12540140651 is a deficient number, since it is larger than the sum of its proper divisors (1).
12540140651 is an equidigital number, since it uses as much as digits as its factorization.
12540140651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4800, while the sum is 29.
The spelling of 12540140651 in words is "twelve billion, five hundred forty million, one hundred forty thousand, six hundred fifty-one".
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