Base | Representation |
---|---|
bin | 10111010110111011… |
… | …10100100011110011 |
3 | 1012100221222012210012 |
4 | 23223131310203303 |
5 | 201140320212221 |
6 | 5432212125135 |
7 | 622522423364 |
oct | 135335644363 |
9 | 35327865705 |
10 | 12540397811 |
11 | 5355800537 |
12 | 251b9067ab |
13 | 124b0c2546 |
14 | 86d6cbb6b |
15 | 4d5e1865b |
hex | 2eb7748f3 |
12540397811 has 2 divisors, whose sum is σ = 12540397812. Its totient is φ = 12540397810.
The previous prime is 12540397763. The next prime is 12540397813. The reversal of 12540397811 is 11879304521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12540397811 - 210 = 12540396787 is a prime.
Together with 12540397813, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12540397813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6270198905 + 6270198906.
It is an arithmetic number, because the mean of its divisors is an integer number (6270198906).
Almost surely, 212540397811 is an apocalyptic number.
12540397811 is a deficient number, since it is larger than the sum of its proper divisors (1).
12540397811 is an equidigital number, since it uses as much as digits as its factorization.
12540397811 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 41.
The spelling of 12540397811 in words is "twelve billion, five hundred forty million, three hundred ninety-seven thousand, eight hundred eleven".
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