Base | Representation |
---|---|
bin | 1011011001111101000001… |
… | …1011010100100101001111 |
3 | 1122101212020110011010001211 |
4 | 2312133100123110211033 |
5 | 3120430424112011033 |
6 | 42401010141115251 |
7 | 2433010303166326 |
oct | 266372033244517 |
9 | 48355213133054 |
10 | 12540506360143 |
11 | 3aa5442a011a3 |
12 | 14a6526258b27 |
13 | 6cc745790ba8 |
14 | 314d6c73d0bd |
15 | 16b319c0d2cd |
hex | b67d06d494f |
12540506360143 has 2 divisors, whose sum is σ = 12540506360144. Its totient is φ = 12540506360142.
The previous prime is 12540506360101. The next prime is 12540506360231. The reversal of 12540506360143 is 34106360504521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12540506360143 - 225 = 12540472805711 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12540506360096 and 12540506360105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12540506367143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6270253180071 + 6270253180072.
It is an arithmetic number, because the mean of its divisors is an integer number (6270253180072).
Almost surely, 212540506360143 is an apocalyptic number.
12540506360143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12540506360143 is an equidigital number, since it uses as much as digits as its factorization.
12540506360143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 40.
Adding to 12540506360143 its reverse (34106360504521), we get a palindrome (46646866864664).
The spelling of 12540506360143 in words is "twelve trillion, five hundred forty billion, five hundred six million, three hundred sixty thousand, one hundred forty-three".
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