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12540554030 = 251439871477
BaseRepresentation
bin10111010110111100…
…11010101100101110
31012100222021011002002
423223132122230232
5201140340212110
65432215332302
7622523644004
oct135336325456
935328234062
1012540554030
1153558a7944
12251b981092
13124b148694
1486d72ca74
154d5e49aa5
hex2eb79ab2e

12540554030 has 16 divisors (see below), whose sum is σ = 22588709760. Its totient is φ = 5012729952.

The previous prime is 12540554027. The next prime is 12540554051. The reversal of 12540554030 is 3045504521.

It is a super-3 number, since 3×125405540303 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12540553984 and 12540554002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 421349 + ... + 450128.

It is an arithmetic number, because the mean of its divisors is an integer number (1411794360).

Almost surely, 212540554030 is an apocalyptic number.

12540554030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12540554030 is a deficient number, since it is larger than the sum of its proper divisors (10048155730).

12540554030 is a wasteful number, since it uses less digits than its factorization.

12540554030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 872923.

The product of its (nonzero) digits is 12000, while the sum is 29.

The spelling of 12540554030 in words is "twelve billion, five hundred forty million, five hundred fifty-four thousand, thirty".

Divisors: 1 2 5 10 1439 2878 7195 14390 871477 1742954 4357385 8714770 1254055403 2508110806 6270277015 12540554030