Base | Representation |
---|---|
bin | 10111010110111100… |
… | …11010101100101110 |
3 | 1012100222021011002002 |
4 | 23223132122230232 |
5 | 201140340212110 |
6 | 5432215332302 |
7 | 622523644004 |
oct | 135336325456 |
9 | 35328234062 |
10 | 12540554030 |
11 | 53558a7944 |
12 | 251b981092 |
13 | 124b148694 |
14 | 86d72ca74 |
15 | 4d5e49aa5 |
hex | 2eb79ab2e |
12540554030 has 16 divisors (see below), whose sum is σ = 22588709760. Its totient is φ = 5012729952.
The previous prime is 12540554027. The next prime is 12540554051. The reversal of 12540554030 is 3045504521.
It is a super-3 number, since 3×125405540303 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12540553984 and 12540554002.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 421349 + ... + 450128.
It is an arithmetic number, because the mean of its divisors is an integer number (1411794360).
Almost surely, 212540554030 is an apocalyptic number.
12540554030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12540554030 is a deficient number, since it is larger than the sum of its proper divisors (10048155730).
12540554030 is a wasteful number, since it uses less digits than its factorization.
12540554030 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 872923.
The product of its (nonzero) digits is 12000, while the sum is 29.
The spelling of 12540554030 in words is "twelve billion, five hundred forty million, five hundred fifty-four thousand, thirty".
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