Base | Representation |
---|---|
bin | 111010011001101110… |
… | …0010110011010011001 |
3 | 102222201112102220002121 |
4 | 1310303130112122121 |
5 | 4023323240341213 |
6 | 133341004101241 |
7 | 12026644641232 |
oct | 1646334263231 |
9 | 388645386077 |
10 | 125417121433 |
11 | 4920977168a |
12 | 20381b34821 |
13 | ba995a0676 |
14 | 60da988089 |
15 | 33e085388d |
hex | 1d33716699 |
125417121433 has 2 divisors, whose sum is σ = 125417121434. Its totient is φ = 125417121432.
The previous prime is 125417121397. The next prime is 125417121463. The reversal of 125417121433 is 334121714521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111377715289 + 14039406144 = 333733^2 + 118488^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-125417121433 is a prime.
It is not a weakly prime, because it can be changed into another prime (125417121463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62708560716 + 62708560717.
It is an arithmetic number, because the mean of its divisors is an integer number (62708560717).
Almost surely, 2125417121433 is an apocalyptic number.
It is an amenable number.
125417121433 is a deficient number, since it is larger than the sum of its proper divisors (1).
125417121433 is an equidigital number, since it uses as much as digits as its factorization.
125417121433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20160, while the sum is 34.
Adding to 125417121433 its reverse (334121714521), we get a palindrome (459538835954).
The spelling of 125417121433 in words is "one hundred twenty-five billion, four hundred seventeen million, one hundred twenty-one thousand, four hundred thirty-three".
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