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12543249240077 is a prime number
BaseRepresentation
bin1011011010000111001111…
…1010100101000000001101
31122102010022121100211222112
42312201303322211000031
53121002033301140302
642402142242353405
72433135260243663
oct266416372450015
948363277324875
1012543249240077
113aa6620215516
1214a6b7095b865
136cca91b0bc7a
1431514cb34c33
1516b42a913552
hexb6873ea500d

12543249240077 has 2 divisors, whose sum is σ = 12543249240078. Its totient is φ = 12543249240076.

The previous prime is 12543249239921. The next prime is 12543249240083. The reversal of 12543249240077 is 77004294234521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12541131491716 + 2117748361 = 3541346^2 + 46019^2 .

It is an emirp because it is prime and its reverse (77004294234521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12543249240077 - 216 = 12543249174541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12543249240097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6271624620038 + 6271624620039.

It is an arithmetic number, because the mean of its divisors is an integer number (6271624620039).

Almost surely, 212543249240077 is an apocalyptic number.

It is an amenable number.

12543249240077 is a deficient number, since it is larger than the sum of its proper divisors (1).

12543249240077 is an equidigital number, since it uses as much as digits as its factorization.

12543249240077 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3386880, while the sum is 50.

The spelling of 12543249240077 in words is "twelve trillion, five hundred forty-three billion, two hundred forty-nine million, two hundred forty thousand, seventy-seven".