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1254333220141 is a prime number
BaseRepresentation
bin10010010000001100000…
…101100000010100101101
311102220122122020200011011
4102100030011200110231
5131022333301021031
62400122134025221
7156423355311451
oct22201405402455
94386578220134
101254333220141
11443a61447611
121831217a8211
139138b008801
14449d254c661
1522964bc76b1
hex1240c16052d

1254333220141 has 2 divisors, whose sum is σ = 1254333220142. Its totient is φ = 1254333220140.

The previous prime is 1254333220097. The next prime is 1254333220159. The reversal of 1254333220141 is 1410223334521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 914643576900 + 339689643241 = 956370^2 + 582829^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1254333220141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1254333220181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627166610070 + 627166610071.

It is an arithmetic number, because the mean of its divisors is an integer number (627166610071).

Almost surely, 21254333220141 is an apocalyptic number.

It is an amenable number.

1254333220141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1254333220141 is an equidigital number, since it uses as much as digits as its factorization.

1254333220141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1254333220141 its reverse (1410223334521), we get a palindrome (2664556554662).

The spelling of 1254333220141 in words is "one trillion, two hundred fifty-four billion, three hundred thirty-three million, two hundred twenty thousand, one hundred forty-one".