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125436131 is a prime number
BaseRepresentation
bin1110111101000…
…00000011100011
322202000211000122
413132200003203
5224102424011
620240310455
73052122002
oct736400343
9282024018
10125436131
1164895027
123601242b
131ccab382
1412932c39
15b02b3db
hex77a00e3

125436131 has 2 divisors, whose sum is σ = 125436132. Its totient is φ = 125436130.

The previous prime is 125436109. The next prime is 125436133. The reversal of 125436131 is 131634521.

It is a strong prime.

It is an emirp because it is prime and its reverse (131634521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125436131 - 26 = 125436067 is a prime.

It is a super-2 number, since 2×1254361312 = 31468445920498322, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 125436133, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 125436131.

It is not a weakly prime, because it can be changed into another prime (125436133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62718065 + 62718066.

It is an arithmetic number, because the mean of its divisors is an integer number (62718066).

Almost surely, 2125436131 is an apocalyptic number.

125436131 is a deficient number, since it is larger than the sum of its proper divisors (1).

125436131 is an equidigital number, since it uses as much as digits as its factorization.

125436131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2160, while the sum is 26.

The square root of 125436131 is about 11199.8272754538. The cubic root of 125436131 is about 500.5808330048.

The spelling of 125436131 in words is "one hundred twenty-five million, four hundred thirty-six thousand, one hundred thirty-one".