Base | Representation |
---|---|
bin | 111010011010011011… |
… | …1100011110100001101 |
3 | 102222210012102122110022 |
4 | 1310310313203310031 |
5 | 4023400401001222 |
6 | 133343220351525 |
7 | 12030355113551 |
oct | 1646467436415 |
9 | 388705378408 |
10 | 125441031437 |
11 | 49221212617 |
12 | 20389b455a5 |
13 | baa15226b7 |
14 | 60ddc0d861 |
15 | 33e29c8042 |
hex | 1d34de3d0d |
125441031437 has 2 divisors, whose sum is σ = 125441031438. Its totient is φ = 125441031436.
The previous prime is 125441031409. The next prime is 125441031449. The reversal of 125441031437 is 734130144521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 91144213801 + 34296817636 = 301901^2 + 185194^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-125441031437 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 125441031397 and 125441031406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125441031337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62720515718 + 62720515719.
It is an arithmetic number, because the mean of its divisors is an integer number (62720515719).
Almost surely, 2125441031437 is an apocalyptic number.
It is an amenable number.
125441031437 is a deficient number, since it is larger than the sum of its proper divisors (1).
125441031437 is an equidigital number, since it uses as much as digits as its factorization.
125441031437 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40320, while the sum is 35.
Adding to 125441031437 its reverse (734130144521), we get a palindrome (859571175958).
The spelling of 125441031437 in words is "one hundred twenty-five billion, four hundred forty-one million, thirty-one thousand, four hundred thirty-seven".
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