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12544440197 is a prime number
BaseRepresentation
bin10111010111011010…
…01111011110000101
31012101020120120220012
423223231033132011
5201142334041242
65432434520005
7622601660642
oct135355173605
935336516805
1012544440197
115358011653
122521136005
13124bba94a3
14870060dc9
154d6466282
hex2ebb4f785

12544440197 has 2 divisors, whose sum is σ = 12544440198. Its totient is φ = 12544440196.

The previous prime is 12544440193. The next prime is 12544440239. The reversal of 12544440197 is 79104444521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12305243041 + 239197156 = 110929^2 + 15466^2 .

It is an emirp because it is prime and its reverse (79104444521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12544440197 - 22 = 12544440193 is a prime.

It is a super-2 number, since 2×125444401972 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12544440193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6272220098 + 6272220099.

It is an arithmetic number, because the mean of its divisors is an integer number (6272220099).

Almost surely, 212544440197 is an apocalyptic number.

It is an amenable number.

12544440197 is a deficient number, since it is larger than the sum of its proper divisors (1).

12544440197 is an equidigital number, since it uses as much as digits as its factorization.

12544440197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 161280, while the sum is 41.

The spelling of 12544440197 in words is "twelve billion, five hundred forty-four million, four hundred forty thousand, one hundred ninety-seven".