Base | Representation |
---|---|
bin | 1011011010001110111100… |
… | …0000101010000011110111 |
3 | 1122102022122112101102122111 |
4 | 2312203233000222003313 |
5 | 3121020300443244343 |
6 | 42403123214511451 |
7 | 2433240405133300 |
oct | 266435700520367 |
9 | 48368575342574 |
10 | 12545314431223 |
11 | 3aa748aa39162 |
12 | 14a7448505587 |
13 | 700030930072 |
14 | 3152a711d7a7 |
15 | 16b4ebda1c9d |
hex | b68ef02a0f7 |
12545314431223 has 6 divisors (see below), whose sum is σ = 14593529032296. Its totient is φ = 10753126655292.
The previous prime is 12545314431211. The next prime is 12545314431257. The reversal of 12545314431223 is 32213441354521.
It is not a de Polignac number, because 12545314431223 - 217 = 12545314300151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12545314431283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 128013412515 + ... + 128013412612.
It is an arithmetic number, because the mean of its divisors is an integer number (2432254838716).
Almost surely, 212545314431223 is an apocalyptic number.
12545314431223 is a deficient number, since it is larger than the sum of its proper divisors (2048214601073).
12545314431223 is an equidigital number, since it uses as much as digits as its factorization.
12545314431223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 256026825141 (or 256026825134 counting only the distinct ones).
The product of its digits is 345600, while the sum is 40.
Adding to 12545314431223 its reverse (32213441354521), we get a palindrome (44758755785744).
The spelling of 12545314431223 in words is "twelve trillion, five hundred forty-five billion, three hundred fourteen million, four hundred thirty-one thousand, two hundred twenty-three".
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