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12545314431257 is a prime number
BaseRepresentation
bin1011011010001110111100…
…0000101010000100011001
31122102022122112101102200202
42312203233000222010121
53121020300443300012
642403123214511545
72433240405133346
oct266435700520431
948368575342622
1012545314431257
113aa748aa39193
1214a74485055b5
1370003093009a
143152a711d7cd
1516b4ebda1cc2
hexb68ef02a119

12545314431257 has 2 divisors, whose sum is σ = 12545314431258. Its totient is φ = 12545314431256.

The previous prime is 12545314431211. The next prime is 12545314431283. The reversal of 12545314431257 is 75213441354521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12377316095881 + 167998335376 = 3518141^2 + 409876^2 .

It is a cyclic number.

It is not a de Polignac number, because 12545314431257 - 26 = 12545314431193 is a prime.

It is not a weakly prime, because it can be changed into another prime (12545314491257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6272657215628 + 6272657215629.

It is an arithmetic number, because the mean of its divisors is an integer number (6272657215629).

Almost surely, 212545314431257 is an apocalyptic number.

It is an amenable number.

12545314431257 is a deficient number, since it is larger than the sum of its proper divisors (1).

12545314431257 is an equidigital number, since it uses as much as digits as its factorization.

12545314431257 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2016000, while the sum is 47.

Adding to 12545314431257 its reverse (75213441354521), we get a palindrome (87758755785778).

The spelling of 12545314431257 in words is "twelve trillion, five hundred forty-five billion, three hundred fourteen million, four hundred thirty-one thousand, two hundred fifty-seven".