Base | Representation |
---|---|
bin | 1011011010001110111100… |
… | …0000101010000011101011 |
3 | 1122102022122112101102122001 |
4 | 2312203233000222003223 |
5 | 3121020300443244321 |
6 | 42403123214511431 |
7 | 2433240405133252 |
oct | 266435700520353 |
9 | 48368575342561 |
10 | 12545314431211 |
11 | 3aa748aa39151 |
12 | 14a7448505577 |
13 | 700030930063 |
14 | 3152a711d799 |
15 | 16b4ebda1c91 |
hex | b68ef02a0eb |
12545314431211 has 2 divisors, whose sum is σ = 12545314431212. Its totient is φ = 12545314431210.
The previous prime is 12545314431193. The next prime is 12545314431257. The reversal of 12545314431211 is 11213441354521.
It is a happy number.
12545314431211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12545314431211 - 211 = 12545314429163 is a prime.
It is not a weakly prime, because it can be changed into another prime (12545314431011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6272657215605 + 6272657215606.
It is an arithmetic number, because the mean of its divisors is an integer number (6272657215606).
Almost surely, 212545314431211 is an apocalyptic number.
12545314431211 is a deficient number, since it is larger than the sum of its proper divisors (1).
12545314431211 is an equidigital number, since it uses as much as digits as its factorization.
12545314431211 is an evil number, because the sum of its binary digits is even.
The product of its digits is 57600, while the sum is 37.
Adding to 12545314431211 its reverse (11213441354521), we get a palindrome (23758755785732).
The spelling of 12545314431211 in words is "twelve trillion, five hundred forty-five billion, three hundred fourteen million, four hundred thirty-one thousand, two hundred eleven".
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