1255003931 has 2 divisors, whose sum is σ = 1255003932. Its totient is φ = 1255003930.

The previous prime is 1255003879. The next prime is 1255003933. The reversal of 1255003931 is 1393005521.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1255003931 is a prime.

It is a super-2 number, since 2×1255003931² = 3150069733650905522, which contains 22 as substring.

Together with 1255003933, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1255003894 and 1255003903.

It is not a weakly prime, because it can be changed into another prime (1255003933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627501965 + 627501966.

It is an arithmetic number, because the mean of its divisors is an integer number (627501966).

Almost surely, 2^1255003931 is an apocalyptic number.

1255003931 is a deficient number, since it is larger than the sum of its proper divisors (1).

1255003931 is an equidigital number, since it uses as much as digits as its factorization.

1255003931 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4050, while the sum is 29.

The square root of 1255003931 is about 35426.0346496754. The cubic root of 1255003931 is about 1078.6528502092.

The spelling of 1255003931 in words is "one billion, two hundred fifty-five million, three thousand, nine hundred thirty-one".