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1255005155473 is a prime number
BaseRepresentation
bin10010010000110100001…
…000101111000010010001
311102222101110121112010221
4102100310020233002101
5131030222304433343
62400312535553041
7156446124544546
oct22206410570221
94388343545127
101255005155473
11444276768573
1218328a82b781
139146729ca94
1444a5789cbcd
15229a3ba45ed
hex1243422f091

1255005155473 has 2 divisors, whose sum is σ = 1255005155474. Its totient is φ = 1255005155472.

The previous prime is 1255005155471. The next prime is 1255005155531. The reversal of 1255005155473 is 3745515005521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1079651917969 + 175353237504 = 1039063^2 + 418752^2 .

It is a cyclic number.

It is not a de Polignac number, because 1255005155473 - 21 = 1255005155471 is a prime.

Together with 1255005155471, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1255005155471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627502577736 + 627502577737.

It is an arithmetic number, because the mean of its divisors is an integer number (627502577737).

Almost surely, 21255005155473 is an apocalyptic number.

It is an amenable number.

1255005155473 is a deficient number, since it is larger than the sum of its proper divisors (1).

1255005155473 is an equidigital number, since it uses as much as digits as its factorization.

1255005155473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 525000, while the sum is 43.

The spelling of 1255005155473 in words is "one trillion, two hundred fifty-five billion, five million, one hundred fifty-five thousand, four hundred seventy-three".