Base | Representation |
---|---|
bin | 10010010000111100110… |
… | …001101011001000100111 |
3 | 11102222202120100201200122 |
4 | 102100330301223020213 |
5 | 131031021411331002 |
6 | 2400335154432155 |
7 | 156452534601362 |
oct | 22207461531047 |
9 | 4388676321618 |
10 | 1255150105127 |
11 | 444340570376 |
12 | 18330b29265b |
13 | 9148b320cc9 |
14 | 44a6cc310d9 |
15 | 229b17876a2 |
hex | 1243cc6b227 |
1255150105127 has 2 divisors, whose sum is σ = 1255150105128. Its totient is φ = 1255150105126.
The previous prime is 1255150105117. The next prime is 1255150105163. The reversal of 1255150105127 is 7215010515521.
It is a weak prime.
It is an emirp because it is prime and its reverse (7215010515521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1255150105127 - 212 = 1255150101031 is a prime.
It is a super-2 number, since 2×12551501051272 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1255150105117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627575052563 + 627575052564.
It is an arithmetic number, because the mean of its divisors is an integer number (627575052564).
Almost surely, 21255150105127 is an apocalyptic number.
1255150105127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1255150105127 is an equidigital number, since it uses as much as digits as its factorization.
1255150105127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17500, while the sum is 35.
The spelling of 1255150105127 in words is "one trillion, two hundred fifty-five billion, one hundred fifty million, one hundred five thousand, one hundred twenty-seven".
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