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12552110215 = 52510422043
BaseRepresentation
bin10111011000010101…
…00000000010000111
31012101210000021011221
423230022200002013
5201201320011330
65433311141211
7623024114341
oct135412400207
935353007157
1012552110215
115361380207
122523814807
131250663668
1487109a291
154d6e7db7a
hex2ec2a0087

12552110215 has 4 divisors (see below), whose sum is σ = 15062532264. Its totient is φ = 10041688168.

The previous prime is 12552110171. The next prime is 12552110227. The reversal of 12552110215 is 51201125521.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12552110215 - 211 = 12552108167 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12552110215.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1255211017 + ... + 1255211026.

It is an arithmetic number, because the mean of its divisors is an integer number (3765633066).

Almost surely, 212552110215 is an apocalyptic number.

12552110215 is a deficient number, since it is larger than the sum of its proper divisors (2510422049).

12552110215 is an equidigital number, since it uses as much as digits as its factorization.

12552110215 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2510422048.

The product of its (nonzero) digits is 1000, while the sum is 25.

Adding to 12552110215 its reverse (51201125521), we get a palindrome (63753235736).

The spelling of 12552110215 in words is "twelve billion, five hundred fifty-two million, one hundred ten thousand, two hundred fifteen".

Divisors: 1 5 2510422043 12552110215