125531355041 has 2 divisors, whose sum is σ = 125531355042. Its totient is φ = 125531355040.

The previous prime is 125531355029. The next prime is 125531355043. The reversal of 125531355041 is 140553135521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125531324416 + 30625 = 354304^2 + 175^2 .

It is a cyclic number.

It is not a de Polignac number, because 125531355041 - 2¹⁰ = 125531354017 is a prime.

It is a super-2 number, since 2×125531355041² (a number of 23 digits) contains 22 as substring.

Together with 125531355043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 125531354992 and 125531355010.

It is not a weakly prime, because it can be changed into another prime (125531355043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62765677520 + 62765677521.

It is an arithmetic number, because the mean of its divisors is an integer number (62765677521).

Almost surely, 2^125531355041 is an apocalyptic number.

It is an amenable number.

125531355041 is a deficient number, since it is larger than the sum of its proper divisors (1).

125531355041 is an equidigital number, since it uses as much as digits as its factorization.

125531355041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45000, while the sum is 35.

The spelling of 125531355041 in words is "one hundred twenty-five billion, five hundred thirty-one million, three hundred fifty-five thousand, forty-one".