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125534112425401 is a prime number
BaseRepresentation
bin11100100010110000110000…
…001011011010010110111001
3121110110221111010122122002011
4130202300300023122112321
5112423222330240103101
61122553324120205521
735304353221514161
oct3442606013322671
9543427433578064
10125534112425401
1136aa9799884279
12120b54283098a1
135507a7b9c97b4
1422ddc523015a1
15e7a66c665751
hex722c302da5b9

125534112425401 has 2 divisors, whose sum is σ = 125534112425402. Its totient is φ = 125534112425400.

The previous prime is 125534112425399. The next prime is 125534112425413. The reversal of 125534112425401 is 104524211435521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108730253664400 + 16803858761001 = 10427380^2 + 4099251^2 .

It is a cyclic number.

It is not a de Polignac number, because 125534112425401 - 21 = 125534112425399 is a prime.

Together with 125534112425399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (125534112425461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62767056212700 + 62767056212701.

It is an arithmetic number, because the mean of its divisors is an integer number (62767056212701).

Almost surely, 2125534112425401 is an apocalyptic number.

It is an amenable number.

125534112425401 is a deficient number, since it is larger than the sum of its proper divisors (1).

125534112425401 is an equidigital number, since it uses as much as digits as its factorization.

125534112425401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192000, while the sum is 40.

The spelling of 125534112425401 in words is "one hundred twenty-five trillion, five hundred thirty-four billion, one hundred twelve million, four hundred twenty-five thousand, four hundred one".