Base | Representation |
---|---|
bin | 10010010001001001000… |
… | …011100010010001011101 |
3 | 11110000021221000001202101 |
4 | 102101021003202101131 |
5 | 131031432131122023 |
6 | 2400411434125101 |
7 | 156460615623361 |
oct | 22211103422135 |
9 | 4400257001671 |
10 | 1255356114013 |
11 | 444436887951 |
12 | 183368280791 |
13 | 914c1c00361 |
14 | 44a8c3392a1 |
15 | 229c48cc1ad |
hex | 124490e245d |
1255356114013 has 2 divisors, whose sum is σ = 1255356114014. Its totient is φ = 1255356114012.
The previous prime is 1255356113983. The next prime is 1255356114029. The reversal of 1255356114013 is 3104116535521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1249841269369 + 5514844644 = 1117963^2 + 74262^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1255356114013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1255356114913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627678057006 + 627678057007.
It is an arithmetic number, because the mean of its divisors is an integer number (627678057007).
Almost surely, 21255356114013 is an apocalyptic number.
It is an amenable number.
1255356114013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1255356114013 is an equidigital number, since it uses as much as digits as its factorization.
1255356114013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 37.
The spelling of 1255356114013 in words is "one trillion, two hundred fifty-five billion, three hundred fifty-six million, one hundred fourteen thousand, thirteen".
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