Base | Representation |
---|---|
bin | 10111011000100101… |
… | …11001001001001001 |
3 | 1012101221011001000111 |
4 | 23230102321021021 |
5 | 201202400411332 |
6 | 5433430234321 |
7 | 623051606341 |
oct | 135422711111 |
9 | 35357131014 |
10 | 12554310217 |
11 | 5362643099 |
12 | 25244b59a1 |
13 | 1250c53b37 |
14 | 8714add21 |
15 | 4d7265947 |
hex | 2ec4b9249 |
12554310217 has 2 divisors, whose sum is σ = 12554310218. Its totient is φ = 12554310216.
The previous prime is 12554310187. The next prime is 12554310247. The reversal of 12554310217 is 71201345521.
It is a balanced prime because it is at equal distance from previous prime (12554310187) and next prime (12554310247).
It can be written as a sum of positive squares in only one way, i.e., 8915325241 + 3638984976 = 94421^2 + 60324^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12554310217 is a prime.
It is a super-2 number, since 2×125543102172 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12554310247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6277155108 + 6277155109.
It is an arithmetic number, because the mean of its divisors is an integer number (6277155109).
Almost surely, 212554310217 is an apocalyptic number.
It is an amenable number.
12554310217 is a deficient number, since it is larger than the sum of its proper divisors (1).
12554310217 is an equidigital number, since it uses as much as digits as its factorization.
12554310217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8400, while the sum is 31.
Adding to 12554310217 its reverse (71201345521), we get a palindrome (83755655738).
The spelling of 12554310217 in words is "twelve billion, five hundred fifty-four million, three hundred ten thousand, two hundred seventeen".
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