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12554498681 is a prime number
BaseRepresentation
bin10111011000100111…
…00111001001111001
31012101221111121112122
423230103213021321
5201202422424211
65433434251025
7623053322654
oct135423471171
935357447478
1012554498681
11536276174a
122524586a75
131250cbb85a
1487151c89b
154d72a16db
hex2ec4e7279

12554498681 has 2 divisors, whose sum is σ = 12554498682. Its totient is φ = 12554498680.

The previous prime is 12554498639. The next prime is 12554498701. The reversal of 12554498681 is 18689445521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7237755625 + 5316743056 = 85075^2 + 72916^2 .

It is a cyclic number.

It is not a de Polignac number, because 12554498681 - 218 = 12554236537 is a prime.

It is a super-2 number, since 2×125544986812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12554498081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6277249340 + 6277249341.

It is an arithmetic number, because the mean of its divisors is an integer number (6277249341).

Almost surely, 212554498681 is an apocalyptic number.

It is an amenable number.

12554498681 is a deficient number, since it is larger than the sum of its proper divisors (1).

12554498681 is an equidigital number, since it uses as much as digits as its factorization.

12554498681 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2764800, while the sum is 53.

The spelling of 12554498681 in words is "twelve billion, five hundred fifty-four million, four hundred ninety-eight thousand, six hundred eighty-one".