Base | Representation |
---|---|
bin | 10111011000100111… |
… | …00111001001111001 |
3 | 1012101221111121112122 |
4 | 23230103213021321 |
5 | 201202422424211 |
6 | 5433434251025 |
7 | 623053322654 |
oct | 135423471171 |
9 | 35357447478 |
10 | 12554498681 |
11 | 536276174a |
12 | 2524586a75 |
13 | 1250cbb85a |
14 | 87151c89b |
15 | 4d72a16db |
hex | 2ec4e7279 |
12554498681 has 2 divisors, whose sum is σ = 12554498682. Its totient is φ = 12554498680.
The previous prime is 12554498639. The next prime is 12554498701. The reversal of 12554498681 is 18689445521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7237755625 + 5316743056 = 85075^2 + 72916^2 .
It is a cyclic number.
It is not a de Polignac number, because 12554498681 - 218 = 12554236537 is a prime.
It is a super-2 number, since 2×125544986812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12554498081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6277249340 + 6277249341.
It is an arithmetic number, because the mean of its divisors is an integer number (6277249341).
Almost surely, 212554498681 is an apocalyptic number.
It is an amenable number.
12554498681 is a deficient number, since it is larger than the sum of its proper divisors (1).
12554498681 is an equidigital number, since it uses as much as digits as its factorization.
12554498681 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2764800, while the sum is 53.
The spelling of 12554498681 in words is "twelve billion, five hundred fifty-four million, four hundred ninety-eight thousand, six hundred eighty-one".
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