Base | Representation |
---|---|
bin | 11100100010111101001011… |
… | …011000010101110000011101 |
3 | 121110112012220220121122212011 |
4 | 130202331023120111300131 |
5 | 112423432141121414044 |
6 | 1123003412022111221 |
7 | 35305334640501634 |
oct | 3442751330256035 |
9 | 543465826548764 |
10 | 125547453701149 |
11 | 370044156651a7 |
12 | 120b7b3027b511 |
13 | 55090c69bb6bc |
14 | 230075a10651b |
15 | e7ab9da2b134 |
hex | 722f4b615c1d |
125547453701149 has 2 divisors, whose sum is σ = 125547453701150. Its totient is φ = 125547453701148.
The previous prime is 125547453701143. The next prime is 125547453701177. The reversal of 125547453701149 is 941107354745521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100350166005049 + 25197287696100 = 10017493^2 + 5019690^2 .
It is a cyclic number.
It is not a de Polignac number, because 125547453701149 - 213 = 125547453692957 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 125547453701093 and 125547453701102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125547453701143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62773726850574 + 62773726850575.
It is an arithmetic number, because the mean of its divisors is an integer number (62773726850575).
Almost surely, 2125547453701149 is an apocalyptic number.
It is an amenable number.
125547453701149 is a deficient number, since it is larger than the sum of its proper divisors (1).
125547453701149 is an equidigital number, since it uses as much as digits as its factorization.
125547453701149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21168000, while the sum is 58.
The spelling of 125547453701149 in words is "one hundred twenty-five trillion, five hundred forty-seven billion, four hundred fifty-three million, seven hundred one thousand, one hundred forty-nine".
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