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12555031331 is a prime number
BaseRepresentation
bin10111011000101011…
…01001001100100011
31012101222111200012102
423230111221030203
5201203042000311
65433453521015
7623061001613
oct135425511443
935358450172
1012555031331
115362a95957
1225247a316b
13125114712b
1487161aa43
154d735943b
hex2ec569323

12555031331 has 2 divisors, whose sum is σ = 12555031332. Its totient is φ = 12555031330.

The previous prime is 12555031249. The next prime is 12555031381. The reversal of 12555031331 is 13313055521.

It is a happy number.

12555031331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12555031331 is a prime.

It is a super-2 number, since 2×125550313312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12555031294 and 12555031303.

It is not a weakly prime, because it can be changed into another prime (12555031381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6277515665 + 6277515666.

It is an arithmetic number, because the mean of its divisors is an integer number (6277515666).

Almost surely, 212555031331 is an apocalyptic number.

12555031331 is a deficient number, since it is larger than the sum of its proper divisors (1).

12555031331 is an equidigital number, since it uses as much as digits as its factorization.

12555031331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6750, while the sum is 29.

Adding to 12555031331 its reverse (13313055521), we get a palindrome (25868086852).

The spelling of 12555031331 in words is "twelve billion, five hundred fifty-five million, thirty-one thousand, three hundred thirty-one".