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12555500555513 is a prime number
BaseRepresentation
bin1011011010110100111000…
…1001101000110011111001
31122110021221102101011022002
42312231032021220303321
53121202131120234023
642411530050510345
72434051002561536
oct266551611506371
948407842334262
1012555500555513
1140008378190a3
1214a940b8953b5
13700c95056b46
14315991c91d8d
1516b8e6277b28
hexb6b4e268cf9

12555500555513 has 2 divisors, whose sum is σ = 12555500555514. Its totient is φ = 12555500555512.

The previous prime is 12555500555467. The next prime is 12555500555531. The reversal of 12555500555513 is 31555500555521.

Together with next prime (12555500555531) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10883579146729 + 1671921408784 = 3299027^2 + 1293028^2 .

It is a cyclic number.

It is not a de Polignac number, because 12555500555513 - 26 = 12555500555449 is a prime.

It is not a weakly prime, because it can be changed into another prime (12555560555513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6277750277756 + 6277750277757.

It is an arithmetic number, because the mean of its divisors is an integer number (6277750277757).

Almost surely, 212555500555513 is an apocalyptic number.

It is an amenable number.

12555500555513 is a deficient number, since it is larger than the sum of its proper divisors (1).

12555500555513 is an equidigital number, since it uses as much as digits as its factorization.

12555500555513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2343750, while the sum is 47.

The spelling of 12555500555513 in words is "twelve trillion, five hundred fifty-five billion, five hundred million, five hundred fifty-five thousand, five hundred thirteen".