Base | Representation |
---|---|
bin | 1011011010111000010101… |
… | …0001100000100000011011 |
3 | 1122110101022212120101010222 |
4 | 2312232011101200200123 |
5 | 3121211024343144111 |
6 | 42412201524430255 |
7 | 2434112632411625 |
oct | 266560521404033 |
9 | 48411285511128 |
10 | 12556425365531 |
11 | 40011718565a3 |
12 | 14a962954838b |
13 | 7010b18290c8 |
14 | 315a3ca29c15 |
15 | 16b94c5557db |
hex | b6b8546081b |
12556425365531 has 2 divisors, whose sum is σ = 12556425365532. Its totient is φ = 12556425365530.
The previous prime is 12556425365527. The next prime is 12556425365543. The reversal of 12556425365531 is 13556352465521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12556425365531 - 22 = 12556425365527 is a prime.
It is a super-2 number, since 2×125564253655312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12556425361531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6278212682765 + 6278212682766.
It is an arithmetic number, because the mean of its divisors is an integer number (6278212682766).
Almost surely, 212556425365531 is an apocalyptic number.
12556425365531 is a deficient number, since it is larger than the sum of its proper divisors (1).
12556425365531 is an equidigital number, since it uses as much as digits as its factorization.
12556425365531 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 16200000, while the sum is 53.
The spelling of 12556425365531 in words is "twelve trillion, five hundred fifty-six billion, four hundred twenty-five million, three hundred sixty-five thousand, five hundred thirty-one".
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